Determining Whether a String Contains Only Numbers using LabVIEW

[jareds]

1. Overview:

This example checks if the string is just a number

2. Description: 

This example will get an string and perform several analysis over to determine if it is a number or if it contains any character. If it is a number, the LED in the front panel will be set to true.

3. Requirements

• LabVIEW 2012 (or compatible)

4. Steps to Implement or Execute Code

1. Insert a string 
2. Run "Check If String is Number LabVIEW 2012 NI Verified.vi"
3. If the string is a number the LED will be set to true

5. Additional Information or References 

 VI Snippet

**This document has been updated to meet the current required format for the NI Code Exchange.** 

[jareds]

This example checks if the string is just a number

2. Description: 

This example will get an string and perform several analysis over to determine if it is a number or if it contains any character. If it is a number, the LED in the front panel will be set to true.

3. Requirements

• LabVIEW 2012 (or compatible)

4. Steps to Implement or Execute Code

1. Insert a string 
2. Run "Check If String is Number LabVIEW 2012 NI Verified.vi"
3. If the string is a number the LED will be set to true

5. Additional Information or References 

[jcarmody]

Or, you could do this:

Or:

[RL123]

add a plus sign or a minus sign:

(^[+-]+[\d]+\.?[\d]*$)|(^[\d]+\.?[\d]*$)|(^\.[\d]+$)

[altenbach]

I probably would use lexical class for the original problem.