dinamically allocate 2d array

[xavi]

I'm trying to dinamically allocate a 2 dimensional array like this:

double **array;

//create array
array = (double **) malloc ( LEN1 );
for (i = 0; i < 8; ++i )
array[i] = (double *) malloc ( 10 );


//fill the array
for (i = 0; i < 8; ++i) {
for (j = 0; j < 10; j++) {
array[i][j] = someValue;
}

The problem is that I don't get the expected size, always creates a smaller array so index goes out of bounds while filling it.
What's wrong in this code?

Thank you.

[ryank]

Your problem is most likely that the argument to malloc is in bytes rather than elements (malloc has no idea that you are allocating doubles.

When you call malloc, you should generally do something like:
array = (double**) malloc (sizeof(double*)*length1);

or
array[i] = (double *) malloc (sizeof(double)*length2);

Regards,
Ryan K.