Rif.: Butterworth Filter

[inuyasha84]

I want to build a Butterworth filter with the formula node. what should I do?

Let's do it step by step and if you can correct me.

I saw the formula for the Butterworth is:

H(jw)=1/sqrt([1+(f/fc)^2n]) 

now I know that the cutoff freq. is fc=1/(2*pi*R*C) where R & C  are variable and choosen by the user (this is what the teacher asked). 

So if i write in the formula node this statments:

Tau=R*C;
Fc=1/(2*pi*Tau);

FdT=abs(1/sqrt([1+(f/Fc)**2*n]));

i got error. why? 

[inuyasha84]

I tried to do some changes but it seems that doesn't work properly.

Can you give a look and help me plz?

Ty

[crossrulz · Accepted solution]

You were close.  But your little loop inside the formula should look like this.  Notice the perithesis around the 2*n.  You were only squaring.  You should raise to a power of 2*n.  I added an input for the number of poles.

for ( f=0; f<1000;f++)
{
  H[f]=1/sqrt(1+(f/Fc)**(2*n));
}

 Also, there's an Absolute Value in the Numeric palette.  Use that instead of the square and square root.

[inuyasha84]

thank you so much i was going crazy!!!