How to open a file dialog and return selected/new file as variable?

[OnlyOne]

Hello,

i am using this expression to open a filedialog and return the selected path.

RunState.Engine.DisplayFileDialog("test","ok","c:\\",StationGlobals.S1,StationGlobals.S2,0,"",4100,"")

How can i enter a new filename in the selected path and return this value into the globals?

Thanks

[CharlieRodway]

Hi,

 You can use the TestStand API by calling an ActiveX step:

Automation Server: TestStand <version> API

Object Reference: Runstate.Engine

Object Class: Engine (IEngine)

Call Method: DisplayOpenFileDialog

The step parameters are self explanatory, but you can return the path using "absolutePath" to a local variable.

I hope this helps,

[OnlyOne]

Hi Charlie,

thanks for your answer.

I think while you wrote the answer i modified my question.

Now i am also doing what you described.. only problem is: how to select a new file (that not exists in dialog).

[CharlieRodway]

Hi,

change the win32flags parameter to the following:

win32Flags: 4100+WinFileDlg_CREATEPROMPT

Regards,

[OnlyOne · Accepted solution]

Works fine.

Thanks. I changed now the 4100 to 0 after reading  the help file:
http://zone.ni.com/reference/en-XX/help/370052G-01/tsapiref/reftopics/windowsfiledialogflags/

Another question is:

The function returns the path in a string array. For example c:\test\sub\new\file.txt

How can i replace ALL \ with \\?

best regards

[OnlyOne]

Solved: SearchAndReplace

[Andrew8675309]

Just a few details.

Automation Server: NI TestStand 2016 SP1 API 

It took me just about forever to find this.

Call Method needs to be selected on the drop down, too.