Yes, and your resolution will be about 31uV (2V/(2^16)).
Here's a link to the manual:
The bits of resolution on your card refers to how many different values your Analog to Digital Converter (ADC) can have. So a 16 bit ADC has 2^16 (=65536) different values it can output over the given input range. This means that the smallest change in input voltage that is significant would be equal to your range divided by the number of values your ADC can convert to.
What is actually going on in the guts of the card is that the ADC has a fixed range of -10V to 10V and can detect an ~305µV change (20V/65536). The range that you specify controls the preamp that scales the data before it reaches the actual ADC. So for example, our +/-1V signal would be amplified 10x before it reaches the 16 bit ADC and then the value the ADC gives back is scaled back down before we read it.
There are some things we do internally that make the absolute accuracy better, so the calculated resolution will be just slightly better than the actual resolution. I have copied table 4-1 out of the user manual (AnalogKid2DigitalMan linked above) which shows the actual resolution for the different ranges:
I hope this answers your question satisfactorily Feel free to post back with any further questions.