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replace an element of a 2d array at any index

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I have a 2d array and I want to insert it into a[1][0]=5

I tried this but not working!

 

gptshubham595_0-1611290966608.png

 

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Solution
Accepted by topic author gptshubham595

Attach a VI rather than a picture.

 

Clean up the code before posting.  I can't clearly tell which constants go to which inputs in your picture.

 

Save the input data as default.  Tell us what you expect vs. what you are getting.

 

What is a[1][0] supposed to mean?

 

I don't understand why you are taking a 2-D array and reshaping into a 1 x 0 array.  So right there you are generating an empty array.  Nothing downstream of that will make any sense.

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Here a[1][0]=5 means 

if a is 

1 2 3

4 5 6

7 8 9 

 

then replace 1st row and 0th col of a i.e 4 with 5

 

Yes Raven you're right replacing that 1,0 for the first block with the size of that matrix worked!

 

but this is creating an empty array as you said, I tried without that first block too but that has the same efffect

 

Anything can be done to replace just an index?

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Hi gpt,

 


@gptshubham595 wrote:

Anything can be done to replace just an index?


Sure: Use ReplaceArraySubset to replace elements/subsets of an array.

Why do you think you need to place additional functions for that purpose?

 

Your questions shows lack of basic LabVIEW knowledge: in your other thread you already got suggestions to take basic LabVIEW training. Did you?

Best regards,
GerdW

using LV2011SP1 + LV2017 (+LV2020 sometimes) on Win10+cRIO
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Message 4 of 9
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Yes, I tried from my side and solved this! 

Thank you!

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Message 5 of 9
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Solution
Accepted by topic author gptshubham595

@gptshubham595 wrote:

Here a[1][0]=5 means 

if a is 

1 2 3

4 5 6

7 8 9 

 

then replace 1st row and 0th col of a i.e 4 with 5

 

Yes Raven you're right replacing that 1,0 for the first block with the size of that matrix worked!

 

but this is creating an empty array as you said, I tried without that first block too but that has the same effect

 

Anything can be done to replace just an index?


Yes.  As I said, get rid of that Reshape Array function.  Just use Replace Array element!

 

What was your thought process that made you put Reshape Array in there?

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Message 6 of 9
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Initially when I was learning I followwe this

Insert Item Into Any Array Index - Discussion Forums - National Instruments (ni.com)

 

 

I saw them using this so I thought to use this

 

 

 

 

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Message 7 of 9
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That example is for inserting a new element into the array.  And the resize array is only uses in the one case where the element to be inserted is after the length of the array.

 

You aren't doing that.  You are replacing an array element that already exists.

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Message 8 of 9
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Yes!

Already Solved that by the way!

 

Thank You! 

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