Hi all
I´m trying to represent a .wav file in a Waveform graph, but, everytime I run my vi, I get an error message saying that there is not enough memory on my system to do it (I have 1Gb of ram).
The .wav file is from a song that I converted from .mp3 to .wav, and is about 50Mb large.
It´s a 16 bit, stereo, 44100 samples per second file.
I understand that this might became much larger once labview starts to handle it, and I tought that the ideial would be to reduce it´s size, by throwing away some uneeded information.
This might be possible, since I only need to see this file in graphical form with a resolution of 1/100´s of seconds.
So, in a 1/100 of a second I should have 441 samples, of which only 1 sample will be enough for my needs.
This way, the load might be reduced 440 times, which is great.
This in theory looks easy, but my problem is how do I do this in practice, without using loops?
Is there a way to create an array by taking a value every 441 samples from the original .wav file, without using a time consuming loop?
I have included my original vi, for you to see my problem.
Try it with a large .wav file.
Thank you all.
