getting one particular element value in an array satisfying a condition given in different array

[jyot445]

hello,

i am having problem in programming of extracting one value(particular element) from an array with a given condition which is dependent on the another array.

for example, lets say i have a set of data from -1v to 1v with their corresponding current . all these data voltage and current are in a two different array .

now if i want to get an element in current corresponding to which the element value in voltage array is zero.how do we find that?

i tried to put in a way as we do in c with two nested loop but here i am not able to do it here.please anyone help me out of it.atleast give a initial 2-3 steps what to do.

[Ken_Naylor · Accepted solution]

Search the voltage array to return the index of the match then use the index to select the item from the second array.  Simple! or am I misunderstanding your problem

Ken

[GerdW · Accepted solution]

Hi iyot,

use Interpolate1DArray:

(Or create an interpolation formula from your values…)

[jyot445]

but what if i am not getting the exact value of it say i want current when voltage is 2 V BUT IN DATA  its slightly greater than or less than it,then how to solve this

[GerdW · Accepted solution]

Hi iyot,

what if i am not getting the exact value of it say i want current when voltage is 2 V BUT IN DATA  its slightly greater than or less than it,then how to solve this

Use the suggestion from my previous post!

It will interpolate (using the Interpolate1DArray function) between the points defined in those voltage/current arrays. Any outliers are limited to min/max of your point array(s).

[jyot445]

thanks a lot 🙂

[jyot445]

well,its not giving the value as required.in short the way you suggested is not working

[Ben]

What Gerd told will work if written correctly.

If your code is not working then there is trouble with your code. Unfortunatly my eye are getting old and I can not quite make out what you have coded from where I am sitting.

Show us the code.

Ben