day of the year out of a specific timestamp

[M.Riede]

Hello,

I want to calculate the day of the year out of a given date. NOT out of the current timestamp which is given by the vi "seconds to date/time" in combination with "day/time to seconds". I do not find the way to  change the content of a timestamp like "bundle by Name" of a Cluster.

Sounds simple, but i don't want to go the way to calculate the day manually concerning leap years.

Thanks in advance,

Magnus

[aputman]

Format date/time string with %j as the format code.

Edit:

[RavensFan]

There is a function called "Seconds to Date/Time".  It outputs a cluster that has an element for day of the year.  Feed whatever timestamp you want into that function.  Only if you don't wire up a timestamp does it give you the current timestamp.

[M.Riede]

Ok, thats my problem. How can I generate a "whatever timestamp" out of e.g. a date in string-format?

[aputman]

If your date format is always the same, you can use Scan From String to convert the string into individual numeric values and then build the cluster into a date/time record and convert that to a timestamp.

[aputman · Accepted solution]

Actually the Scan from String will automatically output the timestamp for you, if you have the proper format code.

[M.Riede]

Ok, now I found it. The challenge for me was to find the format string and the related vi.

Thank you very much !!

Magnus

---