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checksum


@crossrulz wrote:

@GerdW wrote:

Hi Jeff,

 

I don't get your math…

 

How is

checksum = 256 mod (checksum);

equivalent to

if (checksum > 255) checksum -= 255;

???

 

Example:

checksum := 270 (before math routine).

Your result: checksum = (256 mod 270) = 256

OP wanted: checksum = 270-255 = 15

 


Jeff's nomenclature is backwards.  It really should be:

checksum mod 255

That would match what the OP stated.  If you just add bytes and ignore the overflow (the way much checksums work), it would be a mod 256.

 

 


Ah, my C+× IS rusty, not my math! 😉


"Should be" isn't "Is" -Jay
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