05-01-2018 10:04 PM
Hello,
I am a beginner in labview. Can anyone please help me to convert the C programe code to labview code??
#include<stdio.h> int main() { int array[]={1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8,1,1,1,1,1,1,1,1,1,1,1,20,0,40,50,1,1,1,1,1,1,1,1,1,1,5,6,7,8,1,2,3,4}; int n = sizeof(array)/sizeof(array[0]); printf("size of array is :%d \n", n); int i; for(i=0;i<n;i++) { int j=0; int count=0; if(array[i]==1) { j=i; count=1; while(array[j]==1) { j++; count++; } if (count==10) printf("your data is at %d location in array \n",i+count); }
} return 0; }
Basically the code is finding a small sequence of data ,say 10 numbers from a large array of data, say 10000 numbers.
Solved! Go to Solution.
05-01-2018 10:11 PM
I assume you have looked over this: http://www.ni.com/academic/students/learn-labview/
Give it a go and post what you have completed so far so that we can give you specific pointers.
05-02-2018 12:45 AM
Hi sumesh,
Basically the code is finding a small sequence of data ,say 10 numbers from a large array of data, say 10000 numbers.
That's what that code does…
- You need a loop to run over your input array.
- You could use ArraySubset to read a subset of required length.
- You can compare this subset with your predefined pattern you are looking for.
- When both are the very same you can output this "pattern at location %d" message
That's a nice job to learn LabVIEW and some of it's very basic features! (Like autoindexing vs. non-indexing loop tunnels, comparison modes of compare functions, array handling and array functions…)
Show what you have tried and explain where you have failed!
(We will not do your homework!)
05-02-2018 07:07 AM
Just to add to the confusion, we goes use Flatten To String on both the data and the search criteria and then use Search/Split String to do the search for us...