I have implemented the high-pass butterworth filter. The o/p of the signal is correct. when I changed it to band-pass filter. The o/p just disappears.
The filter type is changed from high-pass to band-pass by changing 1to 0 in the filter-type of Butterworth Filter.vi
At least in the version of Butterworth Filter.vi that I found, filtertype for highpass is 1 and bandpass is 2
yes sir, for type 1 i.e. highpass, the output is the processed signal. but when type 2 i.e. bandpass id applied, the output is not visible on the waveform graph
It would be much easier to tell what is going on in your VI if you had actually attached your VI to the post. Include your data as a constant in the block diagram, or as a control where the values are saved as default before saving and attaching.