Set V as the source in Keithley 2400

[paul821102]

Hello,everyone,

   Recently, I want to control Keithley2400 as a Volltage Source,so I want its output is 0 to 5V.

However ,I don't know how I can deal with it.

With many thanks!

[GerdW]

Hi Paul,

you should look into the manual of the Keithley2400! Ther you will find all commands and some explanations...

These are the commands I use in my programs (for 'FormatIntoString' when applying parameters):
switch on Autoranging:    SOUR:VOLT:RANG:AUTO 1
set ouput level:                :SOUR:VOLT:LEV %.;%F
set protection level:         :SENS:CURR:PROT %F (again without smiley: : SENS : CURR : PROT %F)

Well, how to switch off this f*cking smiley, when you don't want them (and they did not appear when editing your message...)?

Message Edited by GerdW on 07-14-2006 10:23 AM

[paul821102]

Thank you for your answer,I'll read the manual carefully and take your suggestion to have a try.I think I can manage this question now.

[wha@atmel]

Hi Paul + Gerd,

o.k. ...... I think you for sure have already solved your problem with K2400 SMU. ...............

But why do you want to invent the wheel again ?    I have different versions of drivers from KEITHLEY's website ( e.g.  kisrcmtr.llb ),

where all the typical commands for this instrument are already done ( not very nice - but it works ).

See @:    http://www.keithley.com/products/currentvoltage/?path=2400/Downloads#2

As I started working with this instrument, there was no driver available - I did it like Gerd described in his mail. Meanwhile I have a set

of vi's for K2400 & K2420 ( use both in our Lab). 

Find attached a pict.  from Frontpanel + Diagram of one of my applications:     V / I - characteristic of  electronic Devices  - for this

example  I took the most simple  -  Diodes.

If you need some more advice - let me know.......

Regards

Werner

[paul821102]

I think it is better to know how you can do with KE2400,in my case I must set the voltage in it.However ,if you want to get other items ,you can set in the instument. This is just my suggestion.