Interpolating 1D XY data not working properly in my sample VI

[edmonton]

Hi Friends,

I need to interpolate XY data acquired from a data acquisition device, the interpolate 1D VI  just takes the nearest value instead of interpolating it, see the attached code. 

The 1D XY data is produced using a square of iteration (Y) and the time (t) at which the Y is obtained. The time interval is 0.2s for data generation and a 50 ms is added for the XY data interpolation. So, the raw data is

(t1, Y1), (t2, Y2), .... (tn, Yn), where Y = i*i, i is the iteration.

The interpolated data should be

(t1+0.05, Y1'), (t2+0.05), Y2'), .... (tn+0.05, Yn'), 

Currently, Yi' = Yi, which is not what I expected.

Could someone help with this issue?

Thanks,

Gu

[altenbach]

Read the help for "interpolate array". Your code makes very little sense.

[altenbach · Accepted solution]

Try this....

[altenbach · Accepted solution]

[Ben_Manthey]

Using the 2D Interpolation makes this all much easier.

[RavensFan]

How is that 2-D interpolation?

The VI is called "Interpolate 1D.vi".

[altenbach]

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@Ben_Manthey wrote:

Using the 2D Interpolation makes this all much easier.

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Your VI is using "interpolate 1D" though. 😉

(also, if you look inside, it is using a scary amount of code to do the same, so it is only simpler on the surface 🐵

[edmonton]

Hi  Dr Altenbach,

Thanks a lots. 

Gu

[edmonton]

Hi Ben,

Thank you for your response. My LV is 2015 can not open the vi, Could I trouble you to save your VI to 2014 or 2015 version and upload it again?

Regards,

Gu

[altenbach]

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@edmonton wrote:

My LV is 2005 can not open the vi,

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Actually, you have LabVIEW 2015. (There is no LabVIEW 2005)