How to increment the row/column index in multicolumn listbox

[Robin11]

Hi

I have developed a program in which the values from the multicolumn list box are read and passed on to some other instrument. To read specific values from the listbox I have used index array to grab the value of a particular cell and pass to the instrument.

Lets say if I want to run the VI multiple times and I want to increment the row index each time the VI runs so that for successive runs the values from the next level of rows are read.

For eg. I have the following listbox

DUT   Vd      Vg

1       0.2     0.3

2       0.4     0.6

So for the first run based on the index which I specify the listbox can read 0.2 and 0.3 and suppose if I run this VI for lets say 2 times during 2nd time it must read 0.4 and 0.6 instead of 0.2 and 0.3.Is there any way to increment the row/column index automatically? Please help me as this is the last step in my project.

Thanks,

Robin

[altenbach]

You would need to keep the index in an uninitialized shift register and increment it with each run.

[Robin11]

thank u ....that works but.....for some reason....when i select N of the for loop as 0 and run multiple times it reads only the 1st row (i.e 0th row as per the multicolumn listbox indexing) but when i select N as 1 and run multiple times....it forgets to read the 1st row (i.e. 0th row of multicolumn list box).

Any suggestions?

[MoReese]

Why would you set the N terminal to 0?  It won't execute the contents of the For loop.  Setting it to 1 will execute once, but without a VI to view, I'm only guessing at to what is going on.  Can you post a VI of what you have?  It would help.

[Robin11]

I was just trying to play with the function and konw how it  works...anyways here is the VI...thanks for ur help...

[altenbach · Accepted solution]

Your VI runs millions of times per second and runs out of elements within nanoseconds. You need to prevent that.

Here's a quick modification that goes to the next row whenever you re-run the VI, and starts over when it runs out of elements.

Maybe it will give you some ideas....

[Robin11]

Hi

That looks gr8. Infact I have modified some portion of it to suit my program. Thank u very much...

Robin