I'm not too familiar with the Gaussian function, however after some quick research I've seen that the:
FWHM = 2 * (sqrt (2*ln 2)) * C
Where I believe C is the centre.
To build this you can either use a math script node or build it using the correct function blocks. I've attached a VI and VI snippet that uses both of these methods. I haven’t wired up the inputs of the Gaussian Function as I am quite unfamiliar with it.
Let me know if this is what you were looking for.
Almost correct: C is not the center, it is standard deviation.
PS. for single variable, single line formulas it is better to use expression node.
If you search for FWHM Gaussian, you can find that the Full Width at Half Maximum (which "answer analysis" should tell you will be related to the Standard Deviation, usually expressed as a lower-case sigma, σ, is
I appreciate the feedback. Silly mistake on my part. Kind of makes me want to go back and check a few of my older forum posts and see if I'm any wiser now or just older haha.
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