04-07-2011 04:39 PM - edited 04-07-2011 04:42 PM
Solved! Go to Solution.
04-07-2011 04:45 PM
04-07-2011 04:52 PM
04-07-2011 05:27 PM
You do have a peak at 10, and also at 990 which corresponds to -10 Hz. You can turn on the FFT shift to get the DC-centered graph.
04-07-2011 09:46 PM
@Darin.K wrote:
You do have a peak at 10, and also at 990 which corresponds to -10 Hz. You can turn on the FFT shift to get the DC-centered graph.
Well, that sure does make sense. I should have zoomed in...I thought it was at 0 and 1000. Thanks for the clarification.
04-03-2014 10:32 PM
hi,I have got a trouble,I do not know what is mean to -500;please help me.
04-07-2014 10:41 AM
The -500 shifts the start point of the waveform. This is required because the shift parameter of the FFT function is set to true.
The following link explains the FFT function in detail:
http://zone.ni.com/reference/en-XX/help/371361K-01/lvanls/fft/