Convert the string "\n" to the newline character

[Mark_Yedinak]

Does anyone know of a quick and elegant way to convert ASCII strings in the form of "\<some character>" to the corresponding byte value. For example, if I have the string "\n" I would like to convert it to the byte value of 0x0A. I realize I could brute force it with a case structure or a lookup table but I need to do this for all of the various escape character sequences. So far I haven't come up with a simple solution.

[JÞB]

Look into vi.lib \Advanced String\ and peek at "Escape String.vi"

While it would be nicer if "Escapes" had an appropriate default value you at least get a frame to start from.  

\vi.lib\Utility\config.llb also contains both an escape and unescape string function that are a bit more user friendly

[Mark_Yedinak]

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@JÞB wrote:

Look into vi.lib \Advanced String\ and peek at "Escape String.vi"

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This works but besides saving a bit of effort creating the lookup this does put me back to the case where I need to add all of teh various escape characters choices. As you mentioned, it would have been really nice if they had those set as the default.

Thanks.

[JÞB]

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@Mark_Yedinak wrote:

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@JÞB wrote:

Look into vi.lib \Advanced String\ and peek at "Escape String.vi"

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This works but besides saving a bit of effort creating the lookup this does put me back to the case where I need to add all of teh various escape characters choices. As you mentioned, it would have been really nice if they had those set as the default.

Thanks.

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That is why I also pointed out \vi.lib\Utility\config.llb\ Escape String.vi and Unescape String.vi.  They are a bit rough on the eyes but better than re-inventing the wheel.

Spoiler

You really don't NEED to open the BDs