Thanks for the input. I understand the steps but even if that is the case, when I'm putting in 1V I should then see a number greater than 32K but I'm seeing apporximately 6K. So I looked at the impedance values of my external output which is 50 Ohms and the impedance of the Analog input signals is 1G Ohms which explains why the voltage seems to be doubled.
It seems to me that 0 - 32K represents 0 -10V respectively and that 64K represents a very small negative number. So 64K - 32K represents a very small negative number to -10 V.
In summary:
-10V = 32768
very small negative number = 64K
0V = 0
+10V = 32767
This is what I'm seeing and can anyone verify if this is correct?