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Aumentar gradualmente 0-5
¡Resuelto!
Since you can calculate the number of iterations needed before the loop starts, a FOR loop is more appropriate than a WHILE loop. You don't even need a shift register. Just multiple [i] with 0.01.
Esta perfecto! Lo he puesto en práctica pero ahora lo quiero hacer que cuando llegue a 5, sea inverso.
Me podrías dar una idea?
Have you actually tested your VI?
You cannot do equal comparisons with DBLs. There is a very high chance that your loop will never stop. The value 0.1 cannot be represented in DBL (you would need an infinite amount of mantissa bits!), so continually adding such a value is not guaranteed to be exactly 5.0, ever (the closest you get is 4.99999999999993783).
The following code will NEVER stop, but go on to infinity (given enough time) because the value is never exactly five!!
That's why I said you need to count iteration, because you can calculate exactly how many iterations are needed!
Also, exclusive OR is probably not the correct boolean operation. (Try a plain OR). Look at the truth table! Your VI will not stop if both conditions are true.
@DavidOrtega wrote:
Esta perfecto! Lo he puesto en práctica pero ahora lo quiero hacer que cuando llegue a 5, sea inverso.
Try something like the following:
(Make sure you fully understand the reason for each part of the code!)
@DavidOrtega wrote:
I have been reviewing your method and it sure does not stop. With the for loop, is it possible to counter up and then down? I mean from 0 to 5 (+0.01) and from 5 to 0 (-0.01).
What do you think?
See my example right above. If you want exactly one up and one down trace, you can again calculate from first principles how many iterations you need, then use a FOR loop with the correct N, based on y-max, dy, and number of desired periods. Simple math!
