X-Chanel must be equidistant ?!?!?

[Ruffy_LR]

Hi there 

With the analysis function "numeric channel to waveform" I had the error "The x-channel must be equidistant" several times now, although the x-channel and the y-channel have the same length.

What am I doing wrong?

In the attachment, you find the signals.

Greetings
Ruffy

[AndreasK · Accepted solution]

If you convert to waveform you are converting your x channel to formular channel

val(n) = offset + factor * n

to be successful you x-channel must be equidistant.

This means if you calculate the delat of you x channel it should be constant.

No as a human being you could argue that it is always 0.4 bt looking on the preview shows you that the computer will never believe this is a constant value.

So either you need to quantizie the values or you you have to stay with an time channel.

[altenbach]

"Equidistant" means that the distance between adjacent points is the same for all points, i.e. graphing [x vs. index] would be a straight line. Nothing to do with the data length.