topic array declaration problem in LabWindows/CVI

array declaration problem

Greber — Thu, 14 Jul 2005 12:12:33 GMT

Hallo everybody,

I don't know why it worked, perhaps the form of declaration is not in the correct style.

What I need:

an 2D array with the size of 10x10 for int values with the name "speed"

Perhaps somebody can give me an example, how it works in LabWindows/CVI 6.0.

Thanks

Florian

Re: array declaration problem

RobertoBozzolo — Thu, 14 Jul 2005 13:22:25 GMT

Why not simply speed[10][10]? This code:

int i, j, speed[10][10];

for (i = 0; i < 10; i++) {
for (j = 0; j < 10; j++) {
speed[i][j] = (i + 1) * (j + 1);
}
}

will produce this result:

speed[x][y]->   0   1   2   3   4   5   6   7   8   9
      |        --------------------------------------
      V
      0 |       1   2   3   4   5   6   7   8   9 10
      1 |       2   4   6   8 10 12 14 16 18 20
      2 |       3   6   9 12 15 18 21 24 27 30
      3 |       4   8 12 16 20 24 28 32 36 40
      4 |       5 10 15 20 25 30 35 40 45 50
      5 |       6 12 18 24 30 36 42 48 54 60
      6 |       7 14 21 28 35 42 49 56 63 70
      7 |       8 16 24 32 40 48 56 64 72 80
      8 |       9 18 27 36 45 54 63 72 81 90
      9 |      10 20 30 40 50 60 70 80 90 100

Re: array declaration problem

Greber — Thu, 14 Jul 2005 15:43:26 GMT

Ok, thx.

But how can I write to / read only one element?

Thx for answering this basic c program problem. Sorry *gg*

Florian

Re: array declaration problem

RobertoBozzolo — Thu, 14 Jul 2005 15:53:23 GMT

You can use every single element of the array exactly as a normal variable:

write to it

speed[row][col] = 1275;

fill by scanning a string

strcpy (a, "123456");

sscanf (a, "%d", &speed[1][1]);

display on a control

SetCtrlVal (panel, contrl, speed[4][5]);

or embed in strings

sprintf (msg, "Speed = %d", speed[3][4]);

Re: array declaration problem

Greber — Thu, 14 Jul 2005 16:37:03 GMT

Thanks, I think now I will find a solution.