le 08-28-2017 04:57 AM
English version:
Hi everyone,
I am currently using Labview communication 2.0.
I started with the simple examples TX / RX continuous async.
I encounter a problem when a want to fetch some data at the RX side of my USRP communication channel.
For example, when I want to send 10200 bits at the TX side (using qam modulation, roll off factor of 1) and I want to fetch 20400 samples at the RX side, I often encounter this message:
"Error -1074118647 occurred at niUSRP Fetch Rx Data (CDB WDT).gvi
Overflow: an internal receive buffer has filled before the data could be returned. Consider reducing the I/Q rate, increasing the Fetch rate, or increasing the number of samples per Fetch. The recommended number of samples per Fetch is a multiple of 1020"
What does it mean? My IQ rate is 1e6 , but what is the fetch rate? the number of sample per fetch?
Thanks in advance.
French version:
Bonjour,
J'utilise Labview communication 2.0. J'ai commencé un projet sur base de l'exemple TX / RX continuous async pour les USRP host. J'ai souvent un problème que je ne comprend pas à la réception. J'obtiens ce message d'erreur.
"Overflow: an internal receive buffer has filled before the data could be returned. Consider reducing the I/Q rate, increasing the Fetch rate, or increasing the number of samples per Fetch. The recommended number of samples per Fetch is a multiple of 1020"
J'envois 10200 bits à TX , je demande de display 20400 samples à RX. Mon IQ rate est de 1e6, j'utilise une modulation QAM et un roll off factor de 1.
A quoi correspond ce fecth rate? ce number of samples per fetch?
Merci d'avance