Swap Bytes

[SercoSteveB]

If Numeric Value In = B'00001111 00000111 00000011 00000001', what is Numeric Value Out following execution of the VI?

a) B'00001111 00000111 00000011 00000001'

b) B'00001111 00000111 00000001 00000011'

c) B'00000111 00001111 00000011 00000001'

d) B'00000111 00001111 00000001 00000011'

[crossrulz]

D

[abcd1234z]

D

[MrStevenUND]

D

[sankar06]

D

[mohamedtanveej17]

Can anyone explain about the answer?

[crossrulz]

The Swap Bytes works at the word level (16 bits).  For for each 16 bits, the bytes are swapped.

[Matt-A.]

D

[mohamedtanveej17]

It's ok...I have 2 doubts..

One is.,that I tried that snippet question into LabVIEW and enter that given string...but it changes to U32 representation's maximum Value...

And one thing.. basically 8bits only be a byte how 16 bits constitute a byte??

[crossrulz]

1. Make sure your display is in binary mode.  Right-click, Visible->Radix.  You should see a little 'b' on the left of the control.  If not, click the symbol and change it.

2.  16 bits is a WORD.  The Swap Bytes swaps the two bytes in a word.  In the case of the U32, it swaps the bytes in each word.

[SercoSteveB]

Answer: D.  Nice one all. 

Who knew that it would action each word in a data type containing multiple words.

[hussey]

Answer D

Swaps the higher order 8 bits and the lower order 8 bits for every word in data.

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@SercoSteveB wrote:

If Numeric Value In = B'00001111 00000111 00000011 00000001', what is Numeric Value Out following execution of the VI?

a) B'00001111 00000111 00000011 00000001'

b) B'00001111 00000111 00000001 00000011'

c) B'00000111 00001111 00000011 00000001'

d) B'00000111 00001111 00000001 00000011'

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[Tsjabrantes]

Hello everyone!

I'm glad to be here. So, according to Swap function the correct answer is letter D.