07-22-2014 12:39 PM
I'm using the NI-DAQ 6008 to output a series of voltages and then reading a sense resistor using the analog input (RSE). I noticed that my analog input is giving me 1.3 V, when I probe it (relative to the device's ground), when completely disconnected. This alters the reading to give me a different measurement of the sense resistor than expected.
Why is my analog input pin non-zero??? Any help would be appreciated. Thanks!
Solved! Go to Solution.
07-22-2014 12:42 PM
It's floating. It could, in theory, be anything without something to somehow tie it to ground. If you have it disconnected, don't read from it.
07-22-2014 12:49 PM
That still doesn't explain things though.
The reading across my resistor using a voltmeter is 2.5V. When I make the same reading using the AI pin, it gives me 1.3 V.
07-22-2014 12:59 PM
07-22-2014 01:04 PM
Explain?
07-22-2014 01:30 PM
catran wrote:
The reading across my resistor using a voltmeter is 2.5V. When I make the same reading using the AI pin, it gives me 1.3 V.
Is one side of the resistor actually tied to ground? If not, that is not a fair comparison. And I thought we were talking about an open to the Analog Input. Maybe pictures of your schematic would be helpful.
07-22-2014 02:24 PM
The 1.3 V is expected. The USB-6008 and -6009 have the world's strangest input circuit. The input impedance is about 144000 ohms terminated into 1.4 V. See the User Guide and Specifications document.
Lynn