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We appreciate your patience as we improve our online experience.
02-01-2013 01:34 AM
hello,
I use a CRC8 because I have no choice. The equipment I use is configured like this and I have programmed with the I2C protocol
Can you tell me which one CRC8 function please
02-01-2013 02:17 AM
02-01-2013 02:20 AM
Yes, but the concern is that I can not make a program to calculate with labview
The formula is:
8bit-CRC: 0x07 = x8 + x2 + x + 1
Can you help me?
thank you
02-01-2013 06:56 AM
I made plenty of conversions for you. Look at those examples. You should just need to change the polynomials to 0x07.
02-04-2013 02:30 AM
hello,
thank you for all of these conversions. But none give the right answer.
What do you mean by: You just need to change shoulds the polynomials to 0x07
thank you
02-04-2013 04:19 AM
Sorry, it is OK
03-27-2013 05:32 AM
my VI