LabVIEW
TCP( EXAM QUESTION ANYONE PLEASE CHECK IT ).
Solved!
@balbal207 wrote:
Design a TCP server to provide the service exam service on the port 50601 .The server expect to read a message made of N bytes with the following structure:
Byte 0: length(u8)
Byte 1:command(u8)
Byte 2...Byte(N-1): Data Bytes (u8)
The first byte represent the message length(N).
The second byte is the command byte.
The remaining bytes are the data bytes.i.e a sequence of u8 representing codes collected from an 8bits analog to digital converter.
Your code has very little resemblance to the stated requirements:
You are only reading one set of data, then spin the loop forever doing the same thing over and over until stop is pressed. almost everything belongs inside the while loop!
You are not even looking at the first receive byte (the lenght!). You need that to decide how much more to read. You need to look at what the read returns, not the size (1) you wire into the read! That's just silly!
How many times do you need to calculate 1/255? Are you expecting different results every time?
What's up with all the coercions and type mismatches?
Why do you wire the net address? What IP is 193.205.4.11?
Do some LabVIEW tutorials. Learn about dataflow and programming basics. Look at the TCP examples that ship with LabVIEW!
@balbal207 wrote:
yes ,but is it correct the command byte and remaining bytes(N-2).so i want to keep only this first one outside and then i have to put command byte and remaining bytes inside the loop
Not is is not correct. In your code N is always 1 and N-2 is thus always -1. You need to process the output of the first read to get N.
No, you need to wait for a connection inside the loop and once a connection is made process the data once (not inside another loop repeating the same operation over and over), then send the response back and close the connection. Then you go back at listening for the next conenction, all inside one loop.
