Plotting 2 arrays

[Veeru]

Hi all

I have 2 separate 1D arrays, i need to plot between X and Y axis.please help me with this

Thanks

veeru

[Dennis_Knutson]

If you would simply turn on Context Help, you would see this when you move your mouse over a graph indicator. To plot two 1D arrays, use the Build Array function to create a 2D array.

I would also refer you again to http://www.ni.com/academic/lv_training/how_learn_lv.htm.

Message Edited by Dennis Knutson on 03-30-2008 07:52 PM

[altenbach]

If one array is X and one array is Y, bundle them into a cluster an wire to an xy graph terminal.

[Veeru]

I tried but its not working out

[Veeru]

I have ttached my program, it may seems too lengthy

In that program from Frame 2 I will get an array and from 3 i will get the other array, i need to plot between these two( i am doing this bit in Frame 4)

Please help me  with this

[Dennis_Knutson]

So, you want an XY Graph? You want to plot one array versus another? Then wire up your bundle function to an XY Graph. You don't have anything wired to it right now.

p.s. There's absolutely no reason to use the sequence structure in your program. It's just making it hard to read.

[Veeru]

Thanks Everyone

Dennis I have wired the bundle to XY Graph, the output waveform is not correct

[altenbach]

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Veeru wrote:

Dennis I have wired the bundle to XY Graph, the output waveform is not correct

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Maybe you could tell us what kind of result you are expecting. You cannot blame the xy graph if you feed it the wrong data. 🙂

In any case, your VI is extremely convoluted. Your sequnce has no purpose and you have three instances of basically the same code. If you place that in a FOR loop with N=3, you can fit the entire code on a postcard. 🙂

Stacked sequences are very distracting because they hide code and sequence locals often force right-to-left wires. There is no reason to force execution order with a sequence. Execution order follows natually from the dataflow.

Here's the same thing simplified. also inclding the xy graph. Maybe it can give you some ideas to simplify your code.

Message Edited by altenbach on 03-30-2008 11:22 PM

[Veeru]

Thanks very much

The reason i repeated 3 times is the signal which i have named as torque is going to be acquired to from test.

Theta is the position information from sincos and i have to plot that with torue signal,so the output is something like the torque signal.

Thanks

[altenbach]

Sorry, but I have no idea what you just wrote... 😉

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Veeru wrote:
The reason i repeated 3 times is the signal which i have named as torque is going to be acquired to from test.

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To repeat things, we use a loop and not duplicate the code N times. How may time do you really need to e.g. calculate "x/2+1" for the same value of x. Once is enough! 

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Veeru wrote:
Theta is the position information from sincos and i have to plot that with torue signal,so the output is something like the torque signal.

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I cannot understand what you are saying. What is the meaning of "something like"? What is X? What is Y?

Do you have a link describing the experiment setup and the math behind it?