01-26-2015 10:35 PM
Yes, we know the exact size of the 2D array and it is always the same. Apparently, the file contains several "chunks", each consisting of two 32 bit numbers and a 2D U8 array. See this post.
Quote:
@AlecSt wrote:
The structure is the following: every time the file is called, the program ought to go to the end of the file and write the following things: the 32 bit seconds count, followed by the 32 bit microseconds count, which is lastly followed by a 2D array (which is always the same size.) This forms one chunk. The file is a lot of chunks concatenated together.
Thus we need to read the two 32bit numbers and the exact number for the 1D U8 array, then reshape the array as I suggested. Repeat for every chunk. The start offset for each chunk is a simple integer multiple of the chunk size, allowing random access to each chunk.
Of course we could also read the entire file as a binary string and chop it up later. 😉
02-05-2015 03:37 PM
Thanks for all the replies. I'll be doing the chopping myself in C code. I was able to read back some files, and you were right about the order of the bits.