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LED Array

Im new at using labView and i have a problem. 

Im trying to create a VI that searches the values of an input array of numbers of a specified value. If the specified value is found in the array the VI shpuld indicate that by turning on an LED and indicating the corresponding index of the array.

 

I would really appreciate if someone could help me with my issue.

 

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Message 1 of 10
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Sounds like homework.  Show us your attempt and we'll help you work through it...  Smiley Happy

LabVIEW Pro Dev & Measurement Studio Pro (VS Pro) 2019 - Unfortunately now moving back to C#, .NET, Python due to forced change to subscription model by NI. 8^{
Message 2 of 10
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This is what i have, but i dont think it rigth. 

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Message 3 of 10
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Nope.  Not right.  You are just determining whether the value you are looking for is equal to the length of your array.

 

Try "Search 1D Array".

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Message 4 of 10
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You're not using Search 1D Array Function, rather you're using Array Size function.

Try out attached code, Index of Element output of Search 1D Array Function is -1 if the element is not found in the input array.


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Message 5 of 10
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@moderator1983 wrote:

 

Try out attached code,



It's generally better to guide them to the solution rather than giving them the answer to their homework.Smiley Wink

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Message 6 of 10
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@RavensFan wrote:

@moderator1983 wrote:

 

Try out attached code,



It's generally better to guide them to the solution rather than giving them the answer to their homework.Smiley Wink


I got it...!! Smiley Happy


I am not allergic to Kudos, in fact I love Kudos.

 Make your LabVIEW experience more CONVENIENT.


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Message 7 of 10
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okay i found the search 1D array. Do i  just add a Equal to function to get to work?

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Message 8 of 10
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Yes you need an equal function.  Actually, you could also use <0 function to determine if the element was found or not.

 

If you read the help for Search 1D Array, you'll see that a value of -1 is returned when the element is not found.

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Message 9 of 10
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Thanks for the help i got the VI to work.

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Message 10 of 10
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