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How to plot two bundled clusters in one graph?

I have an instrument that collects Current readings. I press the Run1 button, and it measures the current at different voltages on a sample. I press the second Run2 button  and it also measures the current at different voltages except this time the sample is illuminated. Both Run1 and Rund 2 generate bundled clusters, which I then plot. What I want is to super-impose these two plots. The problem is  I created/generatde these two bundled clusters (X and Y) separately using two case structures (latch). I try to get the clusters outside the loop, but there's the FALSE condition I have to deal with. How do I get around this?

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Message 1 of 6
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Give this to build array and output of build array give to graph.

 

 

This way should work and bundle should be of time & parameter to be plotted (Make sure)

 

Let me know. 

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Kudos are always welcome if you got solution to some extent.

I need my difficulties because they are necessary to enjoy my success.
--Ranjeet
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Message 2 of 6
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Hard to follow your code description, why not post some code?

A diagram tell more than thousand words 😉


That way you might get the fastest help.

 

 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


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Message 3 of 6
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Here's the VI. Technically I want the bundled array and plot graph out of the Case Structure. But I can't do that. There's a FALSE condition I hae to deal with.

 

 

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Message 4 of 6
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I am attaching you one image. Look at that.

 

Hope this will help you

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Kudos are always welcome if you got solution to some extent.

I need my difficulties because they are necessary to enjoy my success.
--Ranjeet
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Message 5 of 6
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The shift register is your friend. 

 

I did not have the instrument VIs so I used Diagram Disable to make a runnable VI.  I substituted a sine function for the data source.

 

Lynn

Message 6 of 6
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