Error-200284 with DAQmx

[GoviRe]

Hello,

I am trying to make a continuous reading of analogvoltage signal with DAQPad-6015/6016 using sampling rate of 1000 and number of sample=1000 but the DAQmx is showing 

Error-200284 saying that the some or all samples requested have not yet been acquired.

The vi is attached and the images showing the settings of the DAQmx,error mesaage are also attached.

Can I know to solve this error.

Thanks.

[Dennis_Knutson]

Switch from Finite Samples to Continuous. Deleting the Start Task function also seems to work.

[John_P1]

If you delete the Start Task, the read auto-starts the task on each loop iteration.  This would introduce a noticeable delay between each grouping of 1000 samples.  You probably just want to switch to a continuous acquisition.

Best Regards,

[GoviRe]

Thanks.

And when I tried to implement the below  

1)DAQ should acquire the samples for a 1sec and filter the signal  

2)After done with the 1 sec duration of signal acquiring it should go into while loop for the continuous acquiring of signal in which after every 1 sec it should show the signal on the waveform(frontpanell)

I got these problems

1) error as shown in the attached image 2)the timeout ,blocksizes and waveform are shown twice on the frontpanel

Can you suggest how to make a better implementation. I also attached vi .

[John_P1]

Go back to the program that you linked in your first post and change the sample timing type to Continuous.  Don't make any of the other changes you have incorporated (the sequence structure and the wait).

You can add the filtering inside the while loop.  I guess you only want to filter the first set of data and show this statically on the front panel while you continue to acquire and display unfiltered data? You could put the filter VI and the filtered indicator inside a case structure and use the First Call? primitive.

Best Regards,

[GoviRe]

John_P1 thanks for your suggestion.

I will explain a bit clearly of what I am trying to do

I am trying to use an example vi for adaptive filtering using least mean square but I am confused in modifying the example as per my requirements of

1)for the first 1 sec acquired samples I want to filter this signal and want to feed this filtered signal as reference signal d(n) and acquired signal as x(n) to adaptive filtering block

2)After first 1 sec the adaptive filtering vi produces two outputs e(n) and d'(n) .In which the e(n) should be feeded back as input d(n) to the adaptive filtering block and d'(n) is my filtered(required) signal

This feeding of acquired signal for 1 sec interval as x(n) and the previous noise reference=e(n) as other input as d(n) to the adaptive filtering block should be a continuous process.

can you help me out in modifying the example vi of filtering as per my requirements.

[John_P1 · Accepted solution]

That clarifies a bit, it shouldn't be complicated.  Something like this?

Best Regards,

[GoviRe]

thanksalot,

And If possible can I get some clarification like after the 2nd iteration two outputs are generated from the 2nd adaptive block and in this the e(n) is supposed to be fedback as input to the same adaptive filter  and this feedback of  previous otuput as one of the current input should be done for each iteration .can I know how this works with your posted image(vi).

[GoviRe]

Hi,

can someone explain a bit about the above question.

[John_P1]

The resulting e(n) is used as the d(n) input of the next iteration due to the shift register.

Best Regards,