01-25-2017 09:13 AM
Dear sir,
I have an DAQ experiment by using USB-6008 and current transducer, I expect an AC current waveform can be obtained. However, I am confused that the 6008 box converts my AC current signal to DC signal, I cannot recover the orignal AC current waveform from the labview, how can I solve it?
01-25-2017 09:24 AM
That statement doesn't make sense to me. The USB-6008 can read +/- 10 V at up to 10,000 samples/second. So it can read an AC signal.
What do you mean by it converted it to DC?
01-25-2017 09:30 AM
yes, its input can read +-10V ac signal, but its output is 0-5V dc signal, it converts my AC signal to DC signal, I cannot see the AC sinewave.
01-25-2017 09:36 AM
@8022303339 wrote:
yes, its input can read +-10V ac signal, but its output is 0-5V dc signal, it converts my AC signal to DC signal, I cannot see the AC sinewave.
Either we do not understand your problem from your explanation, or you do not understand what are the features of this USB-6008. Maybe you should post a wiring diagram, showing your full assembly with wires...
01-25-2017 09:42 AM - edited 01-25-2017 09:43 AM
Yes. Its analog output is a 0-5V signal at up to 150 samples per second.
You didn't mention anything about outputting the signal you were trying to read.
What exactly are you trying to do and why?