09-21-2011 03:45 PM
You're much better off solving it by hand.
Take the derivative of both equations which removes the constant on the left side of each equation. Then equate them since both are equal to zero. Cancel out F0 and solve. See the attached paper for a rough gide (I might have made some mistakes there) so double check that this is right. Now substitute the constants for their actual values and solve for F0.
Matt,
P.S. please forgive my handwriting.
11-03-2011 02:42 AM
hi.... solve system of equation by using method of elimination for example 3x+6y-2z=12 then we can eliminate the X coefficient by using 3 divided hole equation by 3 then substract original equation 3x+6y-2z=12 and then in second equation we should do eliminate the Y coefficient then in three eliminate the Z and get the value of XYZ and put the value of that in all three equation .thanx..
11-03-2011 02:50 AM
system of equation solved using that first you eliminate the the coefficient of
5a+7b=15
19a-4b=125
a is 5 and dvide the hole equation and substract one then you get the next equation and for other equation eliminate the b coefficient is 19 for same step that are linear equation and you get the value of coefficient a and b then you can put the value of a b in real equation and you can easily solved.
05-12-2014 03:06 PM
Thank you so much for the time you dedicated to answer this question, it has helped me.