CRC8 -> x8 x5 x3 x2 x 1

[DAckermann]

Hello,

I need to calculate a Cyclic Redundancy Check. Can someone help me out with this problem?

The polynomial for this CRC8 is x8 + x5 + x3 + x2 + x + 1. I did not find any standard solution for this type.

Greetings

[Pete.Dunc]

Hi DAckermann,

I can't claim to be an expert but a quick search has thrown up some promising resources:

Inline CRC Reference Library (CRC-32, CRC-16, and CRC-8)

Previous Forum Post

It's always helpful to let us know what you have tried/researched so far 

[DAckermann · Accepted solution]

Hi

I found some pseudocode and was able to solve it by implementing this in LabVIEW.

Thanks.

for (i=Num_Bits; i>=0; i--)
{
xor_5 = CRC_4 ^ CRC_7;
xor_4 = CRC_2 ^ CRC_7;
xor_3 = CRC_1 ^ CRC_7;
xor_2 = CRC_0 ^ CRC_7;
xor_1 = data_in[i] ^ CRC_7;
CRC_7 = CRC_6;
CRC_6 = CRC_5;
CRC_5 = xor_5;
CRC_4 = CRC_3;
CRC_3 = xor_4;
CRC_2 = xor_3;
CRC_1 = xor_2;
CRC_0 = xor_1;
}

[manu23]

hello,

I can convert your VI in version 8.5
please

thank you

cordially

manu23